What are the solutions to the equation x^2-x-18=0 ?

The solutions to the equation x^2-x-18=0 are x=(1+sqrt(73))/2 ,x=(1-sqrt(73))/2

Find the zeros of x^2-x-18=0

The zeros of x^2-x-18=0 are x=(1+sqrt(73))/2 ,x=(1-sqrt(73))/2

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x^{2} - x - 18 = 0

x = \frac{1 + 73}{2}, x = \frac{1 - 73}{2}

Decimal Notation

x = 4.77200 \dots, x = - 3.77200 \dots

Solution steps

x^{2} - x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 18) = 73

x_{1, 2} = \frac{- ( - 1 ) \pm 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 73}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 73}{2 \cdot 1}

x = \frac{- ( - 1 ) + 73}{2 \cdot 1} : \frac{1 + 73}{2}

x = \frac{- ( - 1 ) - 73}{2 \cdot 1} : \frac{1 - 73}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 73}{2}, x = \frac{1 - 73}{2}

u^{4} - v^{4}

x + 6 x = 21 + 15 + 3 x

33 + 33

\frac{3}{5} (5 x + 10) = - 24

x^{2} + 6 x - 40

What are the solutions to the equation x^2-x-18=0 ?
The solutions to the equation x^2-x-18=0 are x=(1+sqrt(73))/2 ,x=(1-sqrt(73))/2
Find the zeros of x^2-x-18=0
The zeros of x^2-x-18=0 are x=(1+sqrt(73))/2 ,x=(1-sqrt(73))/2