What is x^2-9<= |x+3| ?

The solution to x^2-9<= |x+3| is -3<= x<= 4

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x^2-9<= |x+3|

x^{2} - 9 \leq ∣ x + 3 ∣

- 3 \leq x \leq 4

Interval Notation

[- 3, 4]

Solution steps

x^{2} - 9 \leq ∣ x + 3 ∣

Find positive and negative intervals

x < - 3, x \geq - 3

Solve the inequality for each interval

No Solution or - 3 \leq x \leq 4

Merge Overlapping Intervals

- 3 \leq x \leq 4

2 x - 2 = 2 - 2 x

y, ∣ x ∣ - y = 2

\frac{9 x ^{2} - y ^{2}}{21 x + 7 y}

3 x^{2} - x - 4 = - 3 x

\frac{12 a ^{3} + 33 a b ^{2} - 35 a ^{2} b - 10 ab}{4 a - 5 b}