What are the solutions to the equation 7x^2-10x+9=5-2x ?

The solutions to the equation 7x^2-10x+9=5-2x are x= 4/7+i(2sqrt(3))/7 ,x= 4/7-i(2sqrt(3))/7

Find the zeros of 7x^2-10x+9=5-2x

The zeros of 7x^2-10x+9=5-2x are x= 4/7+i(2sqrt(3))/7 ,x= 4/7-i(2sqrt(3))/7

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7 x^{2} - 10 x + 9 = 5 - 2 x

x = \frac{4}{7} + i \frac{2 3}{7}, x = \frac{4}{7} - i \frac{2 3}{7}

Solution steps

7 x^{2} - 10 x + 9 = 5 - 2 x

Move

2 x

to the left side

7 x^{2} - 8 x + 9 = 5

Move

5

to the left side

7 x^{2} - 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 7 \cdot 4}{2 \cdot 7}

Simplify

(- 8)^{2} - 4 \cdot 7 \cdot 4 : 43 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 3 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 3 i}{2 \cdot 7}, x_{2} = \frac{- ( - 8 ) - 4 3 i}{2 \cdot 7}

x = \frac{- ( - 8 ) + 4 3 i}{2 \cdot 7} : \frac{4}{7} + i \frac{2 3}{7}

x = \frac{- ( - 8 ) - 4 3 i}{2 \cdot 7} : \frac{4}{7} - i \frac{2 3}{7}

The solutions to the quadratic equation are:

x = \frac{4}{7} + i \frac{2 3}{7}, x = \frac{4}{7} - i \frac{2 3}{7}

\frac{a ^{2} - 4 a c + 3 b c}{a ^{2} - ab + b c - a c} + \frac{a + 3 b}{b - a} + \frac{a + 2 c}{a - c}

6 = \frac{a}{- 4}

1 0^{0}

(\frac{4}{5}) (\frac{15}{17}) + (- \frac{3}{5}) (\frac{8}{17})

(3.5)^{2}

What are the solutions to the equation 7x^2-10x+9=5-2x ?
The solutions to the equation 7x^2-10x+9=5-2x are x= 4/7+i(2sqrt(3))/7 ,x= 4/7-i(2sqrt(3))/7
Find the zeros of 7x^2-10x+9=5-2x
The zeros of 7x^2-10x+9=5-2x are x= 4/7+i(2sqrt(3))/7 ,x= 4/7-i(2sqrt(3))/7