What are the solutions to the equation -5=9a^2+46a ?

The solutions to the equation -5=9a^2+46a are a=-1/9 ,a=-5

Find the zeros of -5=9a^2+46a

The zeros of -5=9a^2+46a are a=-1/9 ,a=-5

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- 5 = 9 a^{2} + 46 a

a = - \frac{1}{9}, a = - 5

Decimal Notation

a = - 0.11111 \dots, a = - 5

Solution steps

- 5 = 9 a^{2} + 46 a

Switch sides

9 a^{2} + 46 a = - 5

Move

5

to the left side

9 a^{2} + 46 a + 5 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 46 \pm 4 6 ^{2} - 4 \cdot 9 \cdot 5}{2 \cdot 9}

4 6^{2} - 4 \cdot 9 \cdot 5 = 44

a_{1, 2} = \frac{- 46 \pm 44}{2 \cdot 9}

Separate the solutions

a_{1} = \frac{- 46 + 44}{2 \cdot 9}, a_{2} = \frac{- 46 - 44}{2 \cdot 9}

a = \frac{- 46 + 44}{2 \cdot 9} : - \frac{1}{9}

a = \frac{- 46 - 44}{2 \cdot 9} : - 5

The solutions to the quadratic equation are:

a = - \frac{1}{9}, a = - 5

4 x^{2} + 5 x = 6

\frac{x}{3} = - 10

7 (3 x - 4) < 8 (5 x - 1)

9 \cdot 8

- \frac{3}{4} + 5

What are the solutions to the equation -5=9a^2+46a ?
The solutions to the equation -5=9a^2+46a are a=-1/9 ,a=-5
Find the zeros of -5=9a^2+46a
The zeros of -5=9a^2+46a are a=-1/9 ,a=-5