What are the solutions to the equation 0=-25t^2+200t+375 ?

The solutions to the equation 0=-25t^2+200t+375 are t=4-sqrt(31),t=4+sqrt(31)

Find the zeros of 0=-25t^2+200t+375

The zeros of 0=-25t^2+200t+375 are t=4-sqrt(31),t=4+sqrt(31)

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0 = - 25 t^{2} + 200 t + 375

t = 4 - 31, t = 4 + 31

Decimal Notation

t = - 1.56776 \dots, t = 9.56776 \dots

Solution steps

0 = - 25 t^{2} + 200 t + 375

Switch sides

- 25 t^{2} + 200 t + 375 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 200 \pm 20 0 ^{2} - 4 ( - 25 ) \cdot 375}{2 ( - 25 )}

20 0^{2} - 4 (- 25) \cdot 375 = 5031

t_{1, 2} = \frac{- 200 \pm 50 31}{2 ( - 25 )}

Separate the solutions

t_{1} = \frac{- 200 + 50 31}{2 ( - 25 )}, t_{2} = \frac{- 200 - 50 31}{2 ( - 25 )}

t = \frac{- 200 + 50 31}{2 ( - 25 )} : 4 - 31

t = \frac{- 200 - 50 31}{2 ( - 25 )} : 4 + 31

The solutions to the quadratic equation are:

t = 4 - 31, t = 4 + 31

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\frac{2}{13 + 11}

- 38 x + 99 = x^{2} - 38 x - 45

What are the solutions to the equation 0=-25t^2+200t+375 ?
The solutions to the equation 0=-25t^2+200t+375 are t=4-sqrt(31),t=4+sqrt(31)
Find the zeros of 0=-25t^2+200t+375
The zeros of 0=-25t^2+200t+375 are t=4-sqrt(31),t=4+sqrt(31)