What are the solutions to the equation (x-2)^2=3 ?

The solutions to the equation (x-2)^2=3 are x=sqrt(3)+2,x=-sqrt(3)+2

Find the zeros of (x-2)^2=3

The zeros of (x-2)^2=3 are x=sqrt(3)+2,x=-sqrt(3)+2

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(x - 2)^{2} = 3

x = 3 + 2, x = - 3 + 2

Decimal Notation

x = 3.73205 \dots, x = 0.26794 \dots

Solution steps

(x - 2)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 3 : x = 3 + 2

Solve

x - 2 = - 3 : x = - 3 + 2

The solutions to the quadratic equation are:

x = 3 + 2, x = - 3 + 2

\frac{- 2}{i}

\frac{8}{9} \cdot \frac{5}{11} \cdot \frac{1}{2}

4 z^{2} - 9

\frac{3 + i 3}{4 + i 6}

(x - 4) (3 x + 4) = 0

What are the solutions to the equation (x-2)^2=3 ?
The solutions to the equation (x-2)^2=3 are x=sqrt(3)+2,x=-sqrt(3)+2
Find the zeros of (x-2)^2=3
The zeros of (x-2)^2=3 are x=sqrt(3)+2,x=-sqrt(3)+2