What is ((x+3)(x-13))/((x-4)(x+7))<= 0 ?

The solution to ((x+3)(x-13))/((x-4)(x+7))<= 0 is -7<x<=-3\lor 4<x<= 13

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((x+3)(x-13))/((x-4)(x+7))<= 0

\frac{( x + 3 ) ( x - 13 )}{( x - 4 ) ( x + 7 )} \leq 0

- 7 < x \leq - 3 or 4 < x \leq 13

Interval Notation

(- 7, - 3] \cup (4, 13]

Solution steps

\frac{( x + 3 ) ( x - 13 )}{( x - 4 ) ( x + 7 )} \leq 0

Identify the intervals

- 7 < x \leq - 3 or 4 < x \leq 13

∣ y ∣ > 13

(x - 3)^{3} (x - 5) \geq 0

(\frac{16 x ^{5} y ^{10}}{81 x y ^{2}})^{\frac{3}{4}}

lo g_{5} (25) = 3 x + 1

x^{3} - 4 x^{2} - 25 x + 100

What is ((x+3)(x-13))/((x-4)(x+7))<= 0 ?
The solution to ((x+3)(x-13))/((x-4)(x+7))<= 0 is -7<x<=-3\lor 4<x<= 13