What are the solutions to the equation 2x^2+5=0 ?

The solutions to the equation 2x^2+5=0 are x=sqrt(5/2)i,x=-sqrt(5/2)i

Find the zeros of 2x^2+5=0

The zeros of 2x^2+5=0 are x=sqrt(5/2)i,x=-sqrt(5/2)i

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2 x^{2} + 5 = 0

x = \frac{5}{2} i, x = - \frac{5}{2} i

Solution steps

2 x^{2} + 5 = 0

Move

5

to the right side

2 x^{2} = - 5

Divide both sides by

2

x^{2} = - \frac{5}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{5}{2}, x = - - \frac{5}{2}

- \frac{5}{2} = \frac{5}{2} i

- - \frac{5}{2} = - \frac{5}{2} i

x = \frac{5}{2} i, x = - \frac{5}{2} i

x + 4 (x - 3) = 16 - 2 x

(x^{\frac{4}{7}})^{7}

x^{2} + 3 x + 9

\frac{3}{3 ^{- 2}}

x^{1.5}

What are the solutions to the equation 2x^2+5=0 ?
The solutions to the equation 2x^2+5=0 are x=sqrt(5/2)i,x=-sqrt(5/2)i
Find the zeros of 2x^2+5=0
The zeros of 2x^2+5=0 are x=sqrt(5/2)i,x=-sqrt(5/2)i