What are the solutions to the equation x^2-6x=27 ?

The solutions to the equation x^2-6x=27 are x=9,x=-3

Find the zeros of x^2-6x=27

The zeros of x^2-6x=27 are x=9,x=-3

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x^{2} - 6 x = 27

x = 9, x = - 3

Solution steps

x^{2} - 6 x = 27

Move

27

to the left side

x^{2} - 6 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 27) = 12

x_{1, 2} = \frac{- ( - 6 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 12}{2 \cdot 1}

x = \frac{- ( - 6 ) + 12}{2 \cdot 1} : 9

x = \frac{- ( - 6 ) - 12}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 9, x = - 3

7^{2} + 4^{2}

∣ - 3 x - 1 ∣ - 8 > 0

2 (x + 7) \geq 24

- 2 \leq x \leq 2

4 x^{4} - 37 x^{2} + 9

What are the solutions to the equation x^2-6x=27 ?
The solutions to the equation x^2-6x=27 are x=9,x=-3
Find the zeros of x^2-6x=27
The zeros of x^2-6x=27 are x=9,x=-3