What is the domain of f(n)=(n+4)/(10n^2+40n) ?

The domain of f(n)=(n+4)/(10n^2+40n) is n 0

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domain of f(n)=(n+4)/(10n^2+40n)

domain

f (n) = \frac{n + 4}{10 n ^{2} + 40 n}

n < - 4 or - 4 < n < 0 or n > 0

Interval Notation

(- \infty, - 4) \cup (- 4, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

n = 0, n = - 4

The function domain

n < - 4 or - 4 < n < 0 or n > 0

- 3 x = 6

1 + 2 j > 9

- \frac{1}{5} - (- \frac{2}{7})

\frac{( \frac{n}{3} )}{3}

\frac{1}{4} + x < \frac{5}{6}

What is the domain of f(n)=(n+4)/(10n^2+40n) ?
The domain of f(n)=(n+4)/(10n^2+40n) is n<-4\lor-4<n<0\lor n>0