What are the solutions to the equation x^2+14x-32=0 ?

The solutions to the equation x^2+14x-32=0 are x=2,x=-16

Find the zeros of x^2+14x-32=0

The zeros of x^2+14x-32=0 are x=2,x=-16

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x^{2} + 14 x - 32 = 0

x = 2, x = - 16

Solution steps

x^{2} + 14 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 32) = 18

x_{1, 2} = \frac{- 14 \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 18}{2 \cdot 1}, x_{2} = \frac{- 14 - 18}{2 \cdot 1}

x = \frac{- 14 + 18}{2 \cdot 1} : 2

x = \frac{- 14 - 18}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 2, x = - 16

x^{2} - 2 (2 - x) = 2

12 x^{2} - 9 x = 0

5 x + \frac{4 + 4 x}{2} = 23

2 n - 1 - 3 n = 5 n - 7 - 3 n

\frac{4 ( 3 x - 2 )}{3} - \frac{5 ( 8 x - 5 )}{4} = \frac{5}{3}

What are the solutions to the equation x^2+14x-32=0 ?
The solutions to the equation x^2+14x-32=0 are x=2,x=-16
Find the zeros of x^2+14x-32=0
The zeros of x^2+14x-32=0 are x=2,x=-16