What are the solutions to the equation 9b^2+0.27b=0 ?

The solutions to the equation 9b^2+0.27b=0 are b=0,b=-0.03

Find the zeros of 9b^2+0.27b=0

The zeros of 9b^2+0.27b=0 are b=0,b=-0.03

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 b^{2} + 0.27 b = 0

b = 0, b = - 0.03

Solution steps

9 b^{2} + 0.27 b = 0

Factor

9 b^{2} + 0.27 b : b (9 b + 0.27)

b (9 b + 0.27) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

b = 0 or 9 b + 0.27 = 0

Solve

9 b + 0.27 = 0 : b = - 0.03

The solutions to the quadratic equation are:

b = 0, b = - 0.03

\frac{m}{7} = \frac{5 m}{35}

5 - (3 x + 1) = 6

- \frac{1}{( 1 + 2 ) ^{2}}

b^{2} - 100

2 z + 2 < 6

What are the solutions to the equation 9b^2+0.27b=0 ?
The solutions to the equation 9b^2+0.27b=0 are b=0,b=-0.03
Find the zeros of 9b^2+0.27b=0
The zeros of 9b^2+0.27b=0 are b=0,b=-0.03