What are the solutions to the equation -2x^2+8x+73=9 ?

The solutions to the equation -2x^2+8x+73=9 are x=-4,x=8

Find the zeros of -2x^2+8x+73=9

The zeros of -2x^2+8x+73=9 are x=-4,x=8

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- 2 x^{2} + 8 x + 73 = 9

x = - 4, x = 8

Solution steps

- 2 x^{2} + 8 x + 73 = 9

Move

9

to the left side

- 2 x^{2} + 8 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) \cdot 64}{2 ( - 2 )}

8^{2} - 4 (- 2) \cdot 64 = 24

x_{1, 2} = \frac{- 8 \pm 24}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 24}{2 ( - 2 )}, x_{2} = \frac{- 8 - 24}{2 ( - 2 )}

x = \frac{- 8 + 24}{2 ( - 2 )} : - 4

x = \frac{- 8 - 24}{2 ( - 2 )} : 8

The solutions to the quadratic equation are:

x = - 4, x = 8

7 x \leq - 21

\frac{6}{- 10 i}

9 + 4 x = - 10 x - 5

16 S^{4} - 4 T^{2}

\frac{( \frac{π}{8} )}{4}

What are the solutions to the equation -2x^2+8x+73=9 ?
The solutions to the equation -2x^2+8x+73=9 are x=-4,x=8
Find the zeros of -2x^2+8x+73=9
The zeros of -2x^2+8x+73=9 are x=-4,x=8