What are the solutions to the equation 4x^2-20=-6x ?

The solutions to the equation 4x^2-20=-6x are x=(-3+sqrt(89))/4 ,x=-(3+sqrt(89))/4

Find the zeros of 4x^2-20=-6x

The zeros of 4x^2-20=-6x are x=(-3+sqrt(89))/4 ,x=-(3+sqrt(89))/4

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4 x^{2} - 20 = - 6 x

x = \frac{- 3 + 89}{4}, x = - \frac{3 + 89}{4}

Decimal Notation

x = 1.60849 \dots, x = - 3.10849 \dots

Solution steps

4 x^{2} - 20 = - 6 x

Move

6 x

to the left side

4 x^{2} - 20 + 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 6 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 4 ( - 20 )}{2 \cdot 4}

6^{2} - 4 \cdot 4 (- 20) = 289

x_{1, 2} = \frac{- 6 \pm 2 89}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 6 + 2 89}{2 \cdot 4}, x_{2} = \frac{- 6 - 2 89}{2 \cdot 4}

x = \frac{- 6 + 2 89}{2 \cdot 4} : \frac{- 3 + 89}{4}

x = \frac{- 6 - 2 89}{2 \cdot 4} : - \frac{3 + 89}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 89}{4}, x = - \frac{3 + 89}{4}

11 (9^{2})

3 x + 4 = - 2 x - 7

x^{2} - 6 x + 13 = 32

\frac{9 a ^{4} b ^{3} - 3 a ^{3} b ^{4}}{6 a ^{3} b ^{3} - 2 a ^{2} b ^{4}}

\frac{2}{x + 2} > \frac{1}{x + 3}

What are the solutions to the equation 4x^2-20=-6x ?
The solutions to the equation 4x^2-20=-6x are x=(-3+sqrt(89))/4 ,x=-(3+sqrt(89))/4
Find the zeros of 4x^2-20=-6x
The zeros of 4x^2-20=-6x are x=(-3+sqrt(89))/4 ,x=-(3+sqrt(89))/4