What are the solutions to the equation y^2-8y=-9 ?

The solutions to the equation y^2-8y=-9 are y=4+sqrt(7),y=4-sqrt(7)

Find the zeros of y^2-8y=-9

The zeros of y^2-8y=-9 are y=4+sqrt(7),y=4-sqrt(7)

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y^{2} - 8 y = - 9

y = 4 + 7, y = 4 - 7

Decimal Notation

y = 6.64575 \dots, y = 1.35424 \dots

Solution steps

y^{2} - 8 y = - 9

Move

9

to the left side

y^{2} - 8 y + 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 9 = 27

y_{1, 2} = \frac{- ( - 8 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 2 7}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 2 7}{2 \cdot 1}

y = \frac{- ( - 8 ) + 2 7}{2 \cdot 1} : 4 + 7

y = \frac{- ( - 8 ) - 2 7}{2 \cdot 1} : 4 - 7

The solutions to the quadratic equation are:

y = 4 + 7, y = 4 - 7

c^{3} + b^{6}

(3 + i) (4 + 2 i)

x^{8} - 256

9 x \leq x + 15.2

∣ x - 2 ∣ = ∣ 3 x + 4 ∣

What are the solutions to the equation y^2-8y=-9 ?
The solutions to the equation y^2-8y=-9 are y=4+sqrt(7),y=4-sqrt(7)
Find the zeros of y^2-8y=-9
The zeros of y^2-8y=-9 are y=4+sqrt(7),y=4-sqrt(7)