What are the solutions to the equation -x^2+9=0 ?

The solutions to the equation -x^2+9=0 are x=3,x=-3

Find the zeros of -x^2+9=0

The zeros of -x^2+9=0 are x=3,x=-3

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- x^{2} + 9 = 0

x = 3, x = - 3

Solution steps

- x^{2} + 9 = 0

Move

9

to the right side

- x^{2} = - 9

Divide both sides by

- 1

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

(\frac{1}{2} + \frac{1}{4}) - (\frac{1}{3} + \frac{5}{3})

2 x + 1 > 2 + 2 x + 1

9 (- 3) + 4 (- 2) < 14

\frac{2}{6 + 2}

5 x + 10 = 5 x + 20

What are the solutions to the equation -x^2+9=0 ?
The solutions to the equation -x^2+9=0 are x=3,x=-3
Find the zeros of -x^2+9=0
The zeros of -x^2+9=0 are x=3,x=-3