What are the solutions to the equation 12a^2+28a=-8 ?

The solutions to the equation 12a^2+28a=-8 are a=-1/3 ,a=-2

Find the zeros of 12a^2+28a=-8

The zeros of 12a^2+28a=-8 are a=-1/3 ,a=-2

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12 a^{2} + 28 a = - 8

a = - \frac{1}{3}, a = - 2

Decimal Notation

a = - 0.33333 \dots, a = - 2

Solution steps

12 a^{2} + 28 a = - 8

Move

8

to the left side

12 a^{2} + 28 a + 8 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 12 \cdot 8}{2 \cdot 12}

2 8^{2} - 4 \cdot 12 \cdot 8 = 20

a_{1, 2} = \frac{- 28 \pm 20}{2 \cdot 12}

Separate the solutions

a_{1} = \frac{- 28 + 20}{2 \cdot 12}, a_{2} = \frac{- 28 - 20}{2 \cdot 12}

a = \frac{- 28 + 20}{2 \cdot 12} : - \frac{1}{3}

a = \frac{- 28 - 20}{2 \cdot 12} : - 2

The solutions to the quadratic equation are:

a = - \frac{1}{3}, a = - 2

x^{2} + 7 x - 30 = 0

8 - 2 (x + 1) = 7

3 (x - 6) + 2 = 4 (x + 2) - 21

7 v + 7 = 19 v - 3 v + 61

1 0^{5}

What are the solutions to the equation 12a^2+28a=-8 ?
The solutions to the equation 12a^2+28a=-8 are a=-1/3 ,a=-2
Find the zeros of 12a^2+28a=-8
The zeros of 12a^2+28a=-8 are a=-1/3 ,a=-2