What is -(3x)/4 <3\land 4x+6<-3 ?

The solution to -(3x)/4 <3\land 4x+6<-3 is -4<x<-9/4

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-(3x)/4 <3\land 4x+6<-3

- \frac{3 x}{4} < 3 and 4 x + 6 < - 3

- 4 < x < - \frac{9}{4}

Interval Notation

(- 4, - \frac{9}{4})

Decimal Notation

- 4 < x < - 2.25

Solution steps

- \frac{3 x}{4} < 3 and 4 x + 6 < - 3

- \frac{3 x}{4} < 3 : x > - 4

4 x + 6 < - 3 : x < - \frac{9}{4}

Combine the intervals

x > - 4 and x < - \frac{9}{4}

Merge Overlapping Intervals

- 4 < x < - \frac{9}{4}

8 g^{2} - 10 g - 12

\frac{5}{2} + \frac{2}{3}

\frac{14 !}{( 14 - 4 ) !}

- \frac{20}{3} = 10 x - 5 x^{2}

y^{2} + 28 y - 27 = 0

What is -(3x)/4 <3\land 4x+6<-3 ?
The solution to -(3x)/4 <3\land 4x+6<-3 is -4<x<-9/4