What are the solutions to the equation 3x^2-5x=12 ?

The solutions to the equation 3x^2-5x=12 are x=3,x=-4/3

Find the zeros of 3x^2-5x=12

The zeros of 3x^2-5x=12 are x=3,x=-4/3

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3 x^{2} - 5 x = 12

x = 3, x = - \frac{4}{3}

Solution steps

3 x^{2} - 5 x = 12

Move

12

to the left side

3 x^{2} - 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 12) = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 3}

x = \frac{- ( - 5 ) + 13}{2 \cdot 3} : 3

x = \frac{- ( - 5 ) - 13}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 3, x = - \frac{4}{3}

∣ x - 2 ∣ - 2 = 4

- 1 \leq \frac{4 x - 6}{- 3} \leq 0

x^{3} + 4 x^{2} - 8

\frac{6}{5 - 10}

5 p < - 25

What are the solutions to the equation 3x^2-5x=12 ?
The solutions to the equation 3x^2-5x=12 are x=3,x=-4/3
Find the zeros of 3x^2-5x=12
The zeros of 3x^2-5x=12 are x=3,x=-4/3