What are the solutions to the equation m^2+12m-64=0 ?

The solutions to the equation m^2+12m-64=0 are m=4,m=-16

Find the zeros of m^2+12m-64=0

The zeros of m^2+12m-64=0 are m=4,m=-16

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m^{2} + 12 m - 64 = 0

m = 4, m = - 16

Solution steps

m^{2} + 12 m - 64 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 64 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 64) = 20

m_{1, 2} = \frac{- 12 \pm 20}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 12 + 20}{2 \cdot 1}, m_{2} = \frac{- 12 - 20}{2 \cdot 1}

m = \frac{- 12 + 20}{2 \cdot 1} : 4

m = \frac{- 12 - 20}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

m = 4, m = - 16

\frac{x}{2} + 2 x \leq x + 1

\frac{( - 7 ) - 4}{( - 7 ) ^{2} - 16}

15 a - 4 \leq 12 a + 5

k^{2} + 5 k + 6

(x - 6)^{2}

What are the solutions to the equation m^2+12m-64=0 ?
The solutions to the equation m^2+12m-64=0 are m=4,m=-16
Find the zeros of m^2+12m-64=0
The zeros of m^2+12m-64=0 are m=4,m=-16