What is (2/5 m^2)(am-2/7 tm^3-m^4) ?

The solution to (2/5 m^2)(am-2/7 tm^3-m^4) is (2m^2(7ma-2m^3t-7m^4))/(35)

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simplify (2/5 m^2)(am-2/7 tm^3-m^4)

simplify

(\frac{2}{5} m^{2}) (am - \frac{2}{7} t m^{3} - m^{4})

\frac{2 m ^{2} ( 7 ma - 2 m ^{3} t - 7 m ^{4} )}{35}

Solution steps

(\frac{2}{5} m^{2}) (am - \frac{2}{7} t m^{3} - m^{4})

Remove parentheses:

(a) = a

= \frac{2}{5} m^{2} (am - \frac{2}{7} t m^{3} - m^{4})

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 m ^{2}}{5} (- \frac{2}{7} m^{3} t + ma - m^{4})

Multiply

\frac{2}{7} t m^{3} : \frac{2 m ^{3} t}{7}

= \frac{2 m ^{2}}{5} (- \frac{2 m ^{3} t}{7} + ma - m^{4})

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 m ^{2} ( am - \frac{2 t m ^{3}}{7} - m ^{4} )}{5}

Join

am - \frac{2 t m ^{3}}{7} - m^{4} : \frac{7 ma - 2 m ^{3} t - 7 m ^{4}}{7}

= \frac{2 m ^{2} \frac{- 2 m ^{3} t + 7 ma - 7 m ^{4}}{7}}{5}

Multiply

2 m^{2} \frac{am \cdot 7 - 2 t m ^{3} - m ^{4} \cdot 7}{7} : \frac{2 m ^{2} ( - 2 m ^{3} t + 7 ma - 7 m ^{4} )}{7}

= \frac{\frac{2 m ^{2} ( - 2 m ^{3} t + 7 ma - 7 m ^{4} )}{7}}{5}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{( am \cdot 7 - 2 t m ^{3} - m ^{4} \cdot 7 ) \cdot 2 m ^{2}}{7 \cdot 5}

Multiply the numbers:

7 \cdot 5 = 35

= \frac{2 m ^{2} ( - 2 m ^{3} t + 7 ma - 7 m ^{4} )}{35}

- 1.44

- 4 - (- 4)

\frac{2 ( - 0.51 ) + 1}{\frac{1}{4} - ( - 0.5 1 ^{2} )}

2^{k} + 2^{k}

64 y^{2} - 1 = 0

What is (2/5 m^2)(am-2/7 tm^3-m^4) ?
The solution to (2/5 m^2)(am-2/7 tm^3-m^4) is (2m^2(7ma-2m^3t-7m^4))/(35)