What are the solutions to the equation x^2+7x+8=2 ?

The solutions to the equation x^2+7x+8=2 are x=-1,x=-6

Find the zeros of x^2+7x+8=2

The zeros of x^2+7x+8=2 are x=-1,x=-6

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x^{2} + 7 x + 8 = 2

x = - 1, x = - 6

Solution steps

x^{2} + 7 x + 8 = 2

Move

2

to the left side

x^{2} + 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 6 = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 \cdot 1}, x_{2} = \frac{- 7 - 5}{2 \cdot 1}

x = \frac{- 7 + 5}{2 \cdot 1} : - 1

x = \frac{- 7 - 5}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 1, x = - 6

3 s^{2} + 14 s + 8

f^{2} + 24 f - 25

2 (- \frac{2}{3})^{0}

∣ x + 2 ∣ \leq 8

7^{2} \cdot 7^{6}

What are the solutions to the equation x^2+7x+8=2 ?
The solutions to the equation x^2+7x+8=2 are x=-1,x=-6
Find the zeros of x^2+7x+8=2
The zeros of x^2+7x+8=2 are x=-1,x=-6