What is the answer to (4x-7)(2x+3)-8x(x-4)=0 ?

The answer to (4x-7)(2x+3)-8x(x-4)=0 is x= 7/10

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(4x-7)(2x+3)-8x(x-4)=0

(4 x - 7) (2 x + 3) - 8 x (x - 4) = 0

x = \frac{7}{10}

Solution steps

(4 x - 7) (2 x + 3) - 8 x (x - 4) = 0

Expand

(4 x - 7) (2 x + 3) - 8 x (x - 4) : 30 x - 21

30 x - 21 = 0

Move

21

to the right side

30 x = 21

Divide both sides by

30

x = \frac{7}{10}

x (1 + x) = \frac{3}{4}

(1 - a) + 3 (1 - a)^{2} = 0

26 \cdot 33

x^{2} + 5 x - 24 = 0

\frac{11}{15} = w - \frac{8}{15}

What is the answer to (4x-7)(2x+3)-8x(x-4)=0 ?
The answer to (4x-7)(2x+3)-8x(x-4)=0 is x= 7/10
Solve for x: (4x-7)(2x+3)-8x(x-4)=0
The solution is x= 7/10