What are the solutions to the equation s^2+6s+34=0 ?

The solutions to the equation s^2+6s+34=0 are s=-3+5i,s=-3-5i

Find the zeros of s^2+6s+34=0

The zeros of s^2+6s+34=0 are s=-3+5i,s=-3-5i

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s^{2} + 6 s + 34 = 0

s = - 3 + 5 i, s = - 3 - 5 i

Solution steps

s^{2} + 6 s + 34 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 34}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 34 : 10 i

s_{1, 2} = \frac{- 6 \pm 10 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 6 + 10 i}{2 \cdot 1}, s_{2} = \frac{- 6 - 10 i}{2 \cdot 1}

s = \frac{- 6 + 10 i}{2 \cdot 1} : - 3 + 5 i

s = \frac{- 6 - 10 i}{2 \cdot 1} : - 3 - 5 i

The solutions to the quadratic equation are:

s = - 3 + 5 i, s = - 3 - 5 i

\frac{x ^{- 1}}{x ^{- 8}}

- 9 + 6 x > - 15

- 4 x - 8 - 7 x = - 9 + 5 - 11 x

\frac{x}{6} = \frac{64}{8}

- 9 x + 47 + 3 (3 x - 14) = 0

What are the solutions to the equation s^2+6s+34=0 ?
The solutions to the equation s^2+6s+34=0 are s=-3+5i,s=-3-5i
Find the zeros of s^2+6s+34=0
The zeros of s^2+6s+34=0 are s=-3+5i,s=-3-5i