What are the solutions to the equation x^2-x=20 ?

The solutions to the equation x^2-x=20 are x=5,x=-4

Find the zeros of x^2-x=20

The zeros of x^2-x=20 are x=5,x=-4

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x^{2} - x = 20

x = 5, x = - 4

Solution steps

x^{2} - x = 20

Move

20

to the left side

x^{2} - x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

x = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

x = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 5, x = - 4

(w + 1)^{2} = 2 w^{2} + 5 w - 27

\frac{( 2 ( 6 - 2 x ) )}{3} > 8 (111 x + 2)

∣ 6 x - 7 ∣ - 8 = - 17

- \frac{3}{2} - \frac{6}{5} x = \frac{7}{4} - \frac{4}{3} x

- \frac{1}{1.7} e^{- 1.7 (3.3)} = 0.4 e^{2.5 (0)} + C

What are the solutions to the equation x^2-x=20 ?
The solutions to the equation x^2-x=20 are x=5,x=-4
Find the zeros of x^2-x=20
The zeros of x^2-x=20 are x=5,x=-4