What are the solutions to the equation 4z^2+11z-3=0 ?

The solutions to the equation 4z^2+11z-3=0 are z= 1/4 ,z=-3

Find the zeros of 4z^2+11z-3=0

The zeros of 4z^2+11z-3=0 are z= 1/4 ,z=-3

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4 z^{2} + 11 z - 3 = 0

z = \frac{1}{4}, z = - 3

Decimal Notation

z = 0.25, z = - 3

Solution steps

4 z^{2} + 11 z - 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

1 1^{2} - 4 \cdot 4 (- 3) = 13

z_{1, 2} = \frac{- 11 \pm 13}{2 \cdot 4}

Separate the solutions

z_{1} = \frac{- 11 + 13}{2 \cdot 4}, z_{2} = \frac{- 11 - 13}{2 \cdot 4}

z = \frac{- 11 + 13}{2 \cdot 4} : \frac{1}{4}

z = \frac{- 11 - 13}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

z = \frac{1}{4}, z = - 3

3 t + 8 (2 t - 6) = 2 + 14 t

\frac{1}{3} (x + 15) > 4

20 z^{2} - 23 z - 21

(\frac{x ^{- 3}}{y ^{2}})^{- 4}

\frac{d}{d x} ((- \frac{x}{2} + 4)^{2} - 3 (- \frac{x}{2} + 4))

What are the solutions to the equation 4z^2+11z-3=0 ?
The solutions to the equation 4z^2+11z-3=0 are z= 1/4 ,z=-3
Find the zeros of 4z^2+11z-3=0
The zeros of 4z^2+11z-3=0 are z= 1/4 ,z=-3