What are the solutions to the equation -2x^2+5x+13=0 ?

The solutions to the equation -2x^2+5x+13=0 are x=-(-5+sqrt(129))/4 ,x=(5+sqrt(129))/4

Find the zeros of -2x^2+5x+13=0

The zeros of -2x^2+5x+13=0 are x=-(-5+sqrt(129))/4 ,x=(5+sqrt(129))/4

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- 2 x^{2} + 5 x + 13 = 0

x = - \frac{- 5 + 129}{4}, x = \frac{5 + 129}{4}

Decimal Notation

x = - 1.58945 \dots, x = 4.08945 \dots

Solution steps

- 2 x^{2} + 5 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 2 ) \cdot 13}{2 ( - 2 )}

5^{2} - 4 (- 2) \cdot 13 = 129

x_{1, 2} = \frac{- 5 \pm 129}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 5 + 129}{2 ( - 2 )}, x_{2} = \frac{- 5 - 129}{2 ( - 2 )}

x = \frac{- 5 + 129}{2 ( - 2 )} : - \frac{- 5 + 129}{4}

x = \frac{- 5 - 129}{2 ( - 2 )} : \frac{5 + 129}{4}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 129}{4}, x = \frac{5 + 129}{4}

2 x^{2} + 22 x + 60 = 0

(\frac{5}{6})^{6}

x^{2} = 29

e^{- 0.2496}

10000 0^{\frac{2}{5}}

What are the solutions to the equation -2x^2+5x+13=0 ?
The solutions to the equation -2x^2+5x+13=0 are x=-(-5+sqrt(129))/4 ,x=(5+sqrt(129))/4
Find the zeros of -2x^2+5x+13=0
The zeros of -2x^2+5x+13=0 are x=-(-5+sqrt(129))/4 ,x=(5+sqrt(129))/4