What is factor x^{18}-y^{15} ?

The solution to factor x^{18}-y^{15} is (x^6-y^5)(x^{12}+x^6y^5+y^{10})

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factor x^{18}-y^{15}

factor

x^{18} - y^{15}

(x^{6} - y^{5}) (x^{12} + x^{6} y^{5} + y^{10})

Solution steps

x^{18} - y^{15}

Apply exponent rules

= (x^{6})^{3} - (y^{5})^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(x^{6})^{3} - (y^{5})^{3} = (x^{6} - y^{5}) ((x^{6})^{2} + x^{6} y^{5} + (y^{5})^{2})

= (x^{6} - y^{5}) ((x^{6})^{2} + x^{6} y^{5} + (y^{5})^{2})

Simplify

(x^{6})^{2} + x^{6} y^{5} + (y^{5})^{2} : x^{12} + x^{6} y^{5} + y^{10}

= (x^{6} - y^{5}) (x^{12} + x^{6} y^{5} + y^{10})

a = π (8.5)^{2}

- 12 + 7 - 9 \cdot 3

\frac{2 ( x + 1 )}{4} = 3 x - 2

\frac{2}{3} (2 + 2)^{\frac{2}{3}}

3 r + 2 (4 r + 2) < 2 (6 r + 1)

What is factor x^{18}-y^{15} ?
The solution to factor x^{18}-y^{15} is (x^6-y^5)(x^{12}+x^6y^5+y^{10})