What is factor x^4-5x^3-9x^2+81x-108 ?

The solution to factor x^4-5x^3-9x^2+81x-108 is (x-3)^3(x+4)

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factor x^4-5x^3-9x^2+81x-108

factor

x^{4} - 5 x^{3} - 9 x^{2} + 81 x - 108

(x - 3)^{3} (x + 4)

Solution steps

x^{4} - 5 x^{3} - 9 x^{2} + 81 x - 108

Use the rational root theorem

= (x - 3) \frac{x ^{4} - 5 x ^{3} - 9 x ^{2} + 81 x - 108}{x - 3}

\frac{x ^{4} - 5 x ^{3} - 9 x ^{2} + 81 x - 108}{x - 3} = x^{3} - 2 x^{2} - 15 x + 36

= (x - 3) (x^{3} - 2 x^{2} - 15 x + 36)

Factor

x^{3} - 2 x^{2} - 15 x + 36 : (x - 3) (x - 3) (x + 4)

= (x - 3) (x - 3) (x - 3) (x + 4)

Apply exponent rule:

aaa = a^{3}

(x - 3) (x - 3) (x - 3) = (x - 3)^{3}

= (x - 3)^{3} (x + 4)

1 - 3

x^{2} < 4 (x + 3)

3 (a + 10) = 6 (a + 5) - 3 a

x^{\frac{3}{2}} \cdot x^{\frac{3}{2}}

8 - ∣ 2 x + 9 ∣ \leq 7

What is factor x^4-5x^3-9x^2+81x-108 ?
The solution to factor x^4-5x^3-9x^2+81x-108 is (x-3)^3(x+4)