What are the solutions to the equation 5x-x^2=4 ?

The solutions to the equation 5x-x^2=4 are x=1,x=4

Find the zeros of 5x-x^2=4

The zeros of 5x-x^2=4 are x=1,x=4

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5 x - x^{2} = 4

x = 1, x = 4

Solution steps

5 x - x^{2} = 4

Move

4

to the left side

5 x - x^{2} - 4 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

5^{2} - 4 (- 1) (- 4) = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 ( - 1 )}, x_{2} = \frac{- 5 - 3}{2 ( - 1 )}

x = \frac{- 5 + 3}{2 ( - 1 )} : 1

x = \frac{- 5 - 3}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = 1, x = 4

a^{2} = 6.4

x^{2} - 4 x \leq ∣ x ∣

\frac{2 ( 4 p + 1 )}{5} \leq \frac{3 + 12 p}{4}

224 a z + 56 a c - 84 yz - 21 yc

\frac{- 6 + 8 i}{- 4 - 3 i}

What are the solutions to the equation 5x-x^2=4 ?
The solutions to the equation 5x-x^2=4 are x=1,x=4
Find the zeros of 5x-x^2=4
The zeros of 5x-x^2=4 are x=1,x=4