What are the solutions to the equation 4r^2+3r-9=0 ?

The solutions to the equation 4r^2+3r-9=0 are r=(-3+3sqrt(17))/8 ,r=(-3-3sqrt(17))/8

Find the zeros of 4r^2+3r-9=0

The zeros of 4r^2+3r-9=0 are r=(-3+3sqrt(17))/8 ,r=(-3-3sqrt(17))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 r^{2} + 3 r - 9 = 0

r = \frac{- 3 + 3 17}{8}, r = \frac{- 3 - 3 17}{8}

Decimal Notation

r = 1.17116 \dots, r = - 1.92116 \dots

Solution steps

4 r^{2} + 3 r - 9 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 9) = 317

r_{1, 2} = \frac{- 3 \pm 3 17}{2 \cdot 4}

Separate the solutions

r_{1} = \frac{- 3 + 3 17}{2 \cdot 4}, r_{2} = \frac{- 3 - 3 17}{2 \cdot 4}

r = \frac{- 3 + 3 17}{2 \cdot 4} : \frac{- 3 + 3 17}{8}

r = \frac{- 3 - 3 17}{2 \cdot 4} : \frac{- 3 - 3 17}{8}

The solutions to the quadratic equation are:

r = \frac{- 3 + 3 17}{8}, r = \frac{- 3 - 3 17}{8}

x (x - 2) - x = 0

3 x - 6 = 84 - 7 x

4 (x + 6) < 2 x + 8

(x - 9) (x + 4) = 0

\frac{3 x}{4 y ^{2}} - \frac{y}{10 x}

What are the solutions to the equation 4r^2+3r-9=0 ?
The solutions to the equation 4r^2+3r-9=0 are r=(-3+3sqrt(17))/8 ,r=(-3-3sqrt(17))/8
Find the zeros of 4r^2+3r-9=0
The zeros of 4r^2+3r-9=0 are r=(-3+3sqrt(17))/8 ,r=(-3-3sqrt(17))/8