What are the solutions to the equation 4h^2+4h+1=0 ?

The solutions to the equation 4h^2+4h+1=0 are h=-1/2

Find the zeros of 4h^2+4h+1=0

The zeros of 4h^2+4h+1=0 are h=-1/2

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4 h^{2} + 4 h + 1 = 0

h = - \frac{1}{2}

Solution steps

4 h^{2} + 4 h + 1 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

h_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

h = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

h = - \frac{1}{2}

The solution to the quadratic equation is:

h = - \frac{1}{2}

5 x^{2} + 35 x + 60

3 b^{2} - 4 b - 4

- 14 < 6 - 3 x \leq 12

\frac{1}{3} d^{2} + \frac{1}{2} d = - \frac{1}{12}

y^{2} - 14 y = 0

What are the solutions to the equation 4h^2+4h+1=0 ?
The solutions to the equation 4h^2+4h+1=0 are h=-1/2
Find the zeros of 4h^2+4h+1=0
The zeros of 4h^2+4h+1=0 are h=-1/2