What are the solutions to the equation y^2=52y-576 ?

The solutions to the equation y^2=52y-576 are y=36,y=16

Find the zeros of y^2=52y-576

The zeros of y^2=52y-576 are y=36,y=16

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y^{2} = 52 y - 576

y = 36, y = 16

Solution steps

y^{2} = 52 y - 576

Move

576

to the left side

y^{2} + 576 = 52 y

Move

52 y

to the left side

y^{2} + 576 - 52 y = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} - 52 y + 576 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 52 ) \pm ( - 52 ) ^{2} - 4 \cdot 1 \cdot 576}{2 \cdot 1}

(- 52)^{2} - 4 \cdot 1 \cdot 576 = 20

y_{1, 2} = \frac{- ( - 52 ) \pm 20}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 52 ) + 20}{2 \cdot 1}, y_{2} = \frac{- ( - 52 ) - 20}{2 \cdot 1}

y = \frac{- ( - 52 ) + 20}{2 \cdot 1} : 36

y = \frac{- ( - 52 ) - 20}{2 \cdot 1} : 16

The solutions to the quadratic equation are:

y = 36, y = 16

∣ a ∣ > 2 a - 3

4 9^{0.5}

lo g_{x} (2) \cdot lo g_{2} (4 - x) > 0

5 x - 3 < 2 x

\frac{x}{5} - 2 = 0

What are the solutions to the equation y^2=52y-576 ?
The solutions to the equation y^2=52y-576 are y=36,y=16
Find the zeros of y^2=52y-576
The zeros of y^2=52y-576 are y=36,y=16