What are the solutions to the equation 0=3x^2+8x-3 ?

The solutions to the equation 0=3x^2+8x-3 are x= 1/3 ,x=-3

Find the zeros of 0=3x^2+8x-3

The zeros of 0=3x^2+8x-3 are x= 1/3 ,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = 3 x^{2} + 8 x - 3

x = \frac{1}{3}, x = - 3

Decimal Notation

x = 0.33333 \dots, x = - 3

Solution steps

0 = 3 x^{2} + 8 x - 3

Switch sides

3 x^{2} + 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 3) = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 \cdot 3}, x_{2} = \frac{- 8 - 10}{2 \cdot 3}

x = \frac{- 8 + 10}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 8 - 10}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 3

\frac{x + 3}{4} = \frac{x + 4}{5}

7^{2 n} \geq 5 2^{4 n + 3}

x - 6 > \frac{2}{x}

4 (3 x + 5) = 3 (5 x - 3)

7 (x - 8) = - 35

What are the solutions to the equation 0=3x^2+8x-3 ?
The solutions to the equation 0=3x^2+8x-3 are x= 1/3 ,x=-3
Find the zeros of 0=3x^2+8x-3
The zeros of 0=3x^2+8x-3 are x= 1/3 ,x=-3