What are the solutions to the equation 9=-2x^2+3x ?

The solutions to the equation 9=-2x^2+3x are x= 3/4-i(3sqrt(7))/4 ,x= 3/4+i(3sqrt(7))/4

Find the zeros of 9=-2x^2+3x

The zeros of 9=-2x^2+3x are x= 3/4-i(3sqrt(7))/4 ,x= 3/4+i(3sqrt(7))/4

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9 = - 2 x^{2} + 3 x

x = \frac{3}{4} - i \frac{3 7}{4}, x = \frac{3}{4} + i \frac{3 7}{4}

Solution steps

9 = - 2 x^{2} + 3 x

Switch sides

- 2 x^{2} + 3 x = 9

Move

9

to the left side

- 2 x^{2} + 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) ( - 9 )}{2 ( - 2 )}

Simplify

3^{2} - 4 (- 2) (- 9) : 37 i

x_{1, 2} = \frac{- 3 \pm 3 7 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 3 7 i}{2 ( - 2 )}, x_{2} = \frac{- 3 - 3 7 i}{2 ( - 2 )}

x = \frac{- 3 + 3 7 i}{2 ( - 2 )} : \frac{3}{4} - i \frac{3 7}{4}

x = \frac{- 3 - 3 7 i}{2 ( - 2 )} : \frac{3}{4} + i \frac{3 7}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} - i \frac{3 7}{4}, x = \frac{3}{4} + i \frac{3 7}{4}

37 + 57

\frac{28 x - 19}{4 x - 3} \leq 0

\frac{π}{3} + \frac{π}{3}

\frac{x - 1}{4} + 2 \leq x + \frac{1}{2}

4 x - 2 = 38

What are the solutions to the equation 9=-2x^2+3x ?
The solutions to the equation 9=-2x^2+3x are x= 3/4-i(3sqrt(7))/4 ,x= 3/4+i(3sqrt(7))/4
Find the zeros of 9=-2x^2+3x
The zeros of 9=-2x^2+3x are x= 3/4-i(3sqrt(7))/4 ,x= 3/4+i(3sqrt(7))/4