What is (-10+(20i)/n)^2+(-10+(20i)/n) ?

The solution to (-10+(20i)/n)^2+(-10+(20i)/n) is (-400+90n^2}{n^2}-i\frac{380)/n

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simplify (-10+(20i)/n)^2+(-10+(20i)/n)

simplify

(- 10 + \frac{20 i}{n})^{2} + (- 10 + \frac{20 i}{n})

\frac{- 400 + 90 n ^{2}}{n ^{2}} - i \frac{380}{n}

Solution steps

(- 10 + \frac{20 i}{n})^{2} + (- 10 + \frac{20 i}{n})

Remove parentheses:

(- a) = - a

= (- 10 + \frac{20 i}{n})^{2} - 10 + \frac{20 i}{n}

(- 10 + \frac{20 i}{n})^{2} : 100 - \frac{400 i}{n} - \frac{400}{n ^{2}}

= 100 - \frac{400 i}{n} - \frac{400}{n ^{2}} - 10 + \frac{20 i}{n}

Simplify

100 - \frac{400 i}{n} - \frac{400}{n ^{2}} - 10 + \frac{20 i}{n} : 90 - \frac{380 i}{n} - \frac{400}{n ^{2}}

= 90 - \frac{380 i}{n} - \frac{400}{n ^{2}}

Rewrite

90 - \frac{380 i}{n} - \frac{400}{n ^{2}}

in standard complex form:

\frac{90 n ^{2} - 400}{n ^{2}} - \frac{380}{n} i

= \frac{90 n ^{2} - 400}{n ^{2}} - \frac{380}{n} i

\frac{1}{2} x + \frac{3}{2} (x + 1) - \frac{1}{4} = 5

9 + 5

(\frac{7 a ^{4} b ^{- 4}}{2 a ^{2} b ^{2}})^{- 2}

\frac{44}{2} = n + 8

What is (-10+(20i)/n)^2+(-10+(20i)/n) ?
The solution to (-10+(20i)/n)^2+(-10+(20i)/n) is (-400+90n^2}{n^2}-i\frac{380)/n