What is ((7a^4b^{-4})/(2a^2b^2))^{-2} ?

The solution to ((7a^4b^{-4})/(2a^2b^2))^{-2} is (4b^{12})/(49a^4)

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simplify ((7a^4b^{-4})/(2a^2b^2))^{-2}

simplify

(\frac{7 a ^{4} b ^{- 4}}{2 a ^{2} b ^{2}})^{- 2}

\frac{4 b ^{12}}{49 a ^{4}}

Solution steps

(\frac{7 a ^{4} b ^{- 4}}{2 a ^{2} b ^{2}})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{7 a ^{4} b ^{- 4}}{2 a ^{2} b ^{2}})^{- 2} = \frac{1}{( \frac{7 a ^{4} b ^{- 4}}{2 a ^{2} b ^{2}} ) ^{2}}

= \frac{1}{( \frac{7 a ^{4} b ^{- 4}}{2 a ^{2} b ^{2}} ) ^{2}}

Simplify

(\frac{7 a ^{4} b ^{- 4}}{2 a ^{2} b ^{2}})^{2} : \frac{49 a ^{4}}{4 b ^{12}}

= \frac{1}{\frac{49 a ^{4}}{4 b ^{12}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{4 b ^{12}}{49 a ^{4}}

\frac{44}{2} = n + 8

lo g_{3} (27) = y

5 + 3 x = 4 - x

512 m^{4} n^{3}

What is ((7a^4b^{-4})/(2a^2b^2))^{-2} ?
The solution to ((7a^4b^{-4})/(2a^2b^2))^{-2} is (4b^{12})/(49a^4)