What is ((2x^{-3}y)^4)/(8x^2y^2) ?

The solution to ((2x^{-3}y)^4)/(8x^2y^2) is (2y^2)/(x^{14)}

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simplify ((2x^{-3}y)^4)/(8x^2y^2)

simplify

\frac{( 2 x ^{- 3} y ) ^{4}}{8 x ^{2} y ^{2}}

\frac{2 y ^{2}}{x ^{14}}

Solution steps

\frac{( 2 x ^{- 3} y ) ^{4}}{8 x ^{2} y ^{2}}

Simplify

(2 x^{- 3} y)^{4} : 2^{4} \cdot \frac{1}{x ^{12}} y^{4}

= \frac{2 ^{4} \cdot \frac{1}{x ^{12}} y ^{4}}{8 x ^{2} y ^{2}}

Factor the number:

8 = 2^{3}

= \frac{2 ^{4} \cdot \frac{1}{x ^{12}} y ^{4}}{2 ^{3} x ^{2} y ^{2}}

\frac{2 ^{4}}{2 ^{3}} = 2

= \frac{2 \cdot \frac{1}{x ^{12}} y ^{4}}{x ^{2} y ^{2}}

Simplify

\frac{y ^{4}}{y ^{2}} : y^{2}

= \frac{2 \cdot \frac{1}{x ^{12}} y ^{2}}{x ^{2}}

Simplify

\frac{2 \cdot \frac{1}{x ^{12}} y ^{2}}{x ^{2}} : \frac{2 y ^{2}}{x ^{14}}

= \frac{2 y ^{2}}{x ^{14}}

\frac{7}{2} - \frac{9}{4}

2 x \leq - 7

(0.2)^{4}

\frac{5}{6} - \frac{2}{9}

6 x^{2} + 31 x + 5

What is ((2x^{-3}y)^4)/(8x^2y^2) ?
The solution to ((2x^{-3}y)^4)/(8x^2y^2) is (2y^2)/(x^{14)}