What are the solutions to the equation 4p^2-p=0 ?

The solutions to the equation 4p^2-p=0 are p= 1/4 ,p=0

Find the zeros of 4p^2-p=0

The zeros of 4p^2-p=0 are p= 1/4 ,p=0

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4 p^{2} - p = 0

p = \frac{1}{4}, p = 0

Decimal Notation

p = 0.25, p = 0

Solution steps

4 p^{2} - p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 1)^{2} - 4 \cdot 4 \cdot 0 = 1

p_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 4}, p_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 4}

p = \frac{- ( - 1 ) + 1}{2 \cdot 4} : \frac{1}{4}

p = \frac{- ( - 1 ) - 1}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

p = \frac{1}{4}, p = 0

3 x - 15 = 2 x + 5

\frac{1}{8} + \frac{1}{4}

\frac{1}{4} k = \frac{3}{8} k - \frac{1}{4}

\frac{2 a ^{3} - 32 a}{2 a ^{3} + 16 a ^{2} + 32 a}

- 8 a b^{2} + a^{2} b + 15 b^{3}

What are the solutions to the equation 4p^2-p=0 ?
The solutions to the equation 4p^2-p=0 are p= 1/4 ,p=0
Find the zeros of 4p^2-p=0
The zeros of 4p^2-p=0 are p= 1/4 ,p=0