What is factor 2x^5+4x^4-x^3-2x^2-x-2 ?

The solution to factor 2x^5+4x^4-x^3-2x^2-x-2 is (x-1)(x+1)(x+2)(2x^2+1)

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factor 2x^5+4x^4-x^3-2x^2-x-2

factor

2 x^{5} + 4 x^{4} - x^{3} - 2 x^{2} - x - 2

(x - 1) (x + 1) (x + 2) (2 x^{2} + 1)

Solution steps

2 x^{5} + 4 x^{4} - x^{3} - 2 x^{2} - x - 2

Use the rational root theorem

= (x - 1) \frac{2 x ^{5} + 4 x ^{4} - x ^{3} - 2 x ^{2} - x - 2}{x - 1}

\frac{2 x ^{5} + 4 x ^{4} - x ^{3} - 2 x ^{2} - x - 2}{x - 1} = 2 x^{4} + 6 x^{3} + 5 x^{2} + 3 x + 2

= (x - 1) (2 x^{4} + 6 x^{3} + 5 x^{2} + 3 x + 2)

Factor

2 x^{4} + 6 x^{3} + 5 x^{2} + 3 x + 2 : (x + 1) (x + 2) (2 x^{2} + 1)

= (x - 1) (x + 1) (x + 2) (2 x^{2} + 1)

- 4 y + 14 = - 2 y + 4

7 (2 x - 1) - 3 (4 x - 1) = 4 (3 x + 2) - 1

13.5 = 3 1.54 \cdot 1200 - 28.93 + 2.52

\frac{x ^{- 1} y ^{- 2}}{z ^{- 3}}

2 (6 x + 9) \geq 12 x + 22

What is factor 2x^5+4x^4-x^3-2x^2-x-2 ?
The solution to factor 2x^5+4x^4-x^3-2x^2-x-2 is (x-1)(x+1)(x+2)(2x^2+1)