What are the solutions to the equation x^2+10x-155=0 ?

The solutions to the equation x^2+10x-155=0 are x=-5+6sqrt(5),x=-5-6sqrt(5)

Find the zeros of x^2+10x-155=0

The zeros of x^2+10x-155=0 are x=-5+6sqrt(5),x=-5-6sqrt(5)

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x^{2} + 10 x - 155 = 0

x = - 5 + 65, x = - 5 - 65

Solution steps

x^{2} + 10 x - 155 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 155 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 155) = 125

x_{1, 2} = \frac{- 10 \pm 12 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 12 5}{2 \cdot 1}, x_{2} = \frac{- 10 - 12 5}{2 \cdot 1}

x = \frac{- 10 + 12 5}{2 \cdot 1} : - 5 + 65

x = \frac{- 10 - 12 5}{2 \cdot 1} : - 5 - 65

The solutions to the quadratic equation are:

x = - 5 + 65, x = - 5 - 65

125 u^{3} + 27

\frac{6 x - 1}{4} - \frac{5 - 2 x}{2} = 1

4 x^{2} - 20 x + 25 = 10

3 < 3 - x < 5

- 6 \leq 3 (5 v - 2)

What are the solutions to the equation x^2+10x-155=0 ?
The solutions to the equation x^2+10x-155=0 are x=-5+6sqrt(5),x=-5-6sqrt(5)
Find the zeros of x^2+10x-155=0
The zeros of x^2+10x-155=0 are x=-5+6sqrt(5),x=-5-6sqrt(5)