What are the solutions to the equation 4x^2+25=0 ?

The solutions to the equation 4x^2+25=0 are x= 5/2 i,x=-5/2 i

Find the zeros of 4x^2+25=0

The zeros of 4x^2+25=0 are x= 5/2 i,x=-5/2 i

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4 x^{2} + 25 = 0

x = \frac{5}{2} i, x = - \frac{5}{2} i

Solution steps

4 x^{2} + 25 = 0

Move

25

to the right side

4 x^{2} = - 25

Divide both sides by

4

x^{2} = - \frac{25}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{25}{4}, x = - - \frac{25}{4}

- \frac{25}{4} = \frac{5}{2} i

- - \frac{25}{4} = - \frac{5}{2} i

x = \frac{5}{2} i, x = - \frac{5}{2} i

\frac{81}{4}

- \frac{1}{5} x - 5 < 11

2 x - (x + 1)^{2} = 3 x^{2} - 6

2 q^{2} - 13 q + 20 = 0

3 a^{2} - 3 a - 6

What are the solutions to the equation 4x^2+25=0 ?
The solutions to the equation 4x^2+25=0 are x= 5/2 i,x=-5/2 i
Find the zeros of 4x^2+25=0
The zeros of 4x^2+25=0 are x= 5/2 i,x=-5/2 i