What are the solutions to the equation -3x+3=3x^2+x+4x^2 ?

The solutions to the equation -3x+3=3x^2+x+4x^2 are x= 3/7 ,x=-1

Find the zeros of -3x+3=3x^2+x+4x^2

The zeros of -3x+3=3x^2+x+4x^2 are x= 3/7 ,x=-1

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- 3 x + 3 = 3 x^{2} + x + 4 x^{2}

x = \frac{3}{7}, x = - 1

Solution steps

- 3 x + 3 = 3 x^{2} + x + 4 x^{2}

Refine

- 3 x + 3 = 7 x^{2} + x

Switch sides

7 x^{2} + x = - 3 x + 3

Move

3

to the left side

7 x^{2} + x - 3 = - 3 x

Move

3 x

to the left side

7 x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 7 ( - 3 )}{2 \cdot 7}

4^{2} - 4 \cdot 7 (- 3) = 10

x_{1, 2} = \frac{- 4 \pm 10}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 4 + 10}{2 \cdot 7}, x_{2} = \frac{- 4 - 10}{2 \cdot 7}

x = \frac{- 4 + 10}{2 \cdot 7} : \frac{3}{7}

x = \frac{- 4 - 10}{2 \cdot 7} : - 1

The solutions to the quadratic equation are:

x = \frac{3}{7}, x = - 1

(2 x + 3) (3 x - 1) (x - 2) < 0

- 824 - 52 \cdot (712 - 23)

4 y + 6 = 90 - 8 y

x^{3} \leq 6 x^{2} + 9 x

i^{84}

What are the solutions to the equation -3x+3=3x^2+x+4x^2 ?
The solutions to the equation -3x+3=3x^2+x+4x^2 are x= 3/7 ,x=-1
Find the zeros of -3x+3=3x^2+x+4x^2
The zeros of -3x+3=3x^2+x+4x^2 are x= 3/7 ,x=-1