What are the solutions to the equation x^2+x-31=0 ?

The solutions to the equation x^2+x-31=0 are x=(-1+5sqrt(5))/2 ,x=(-1-5sqrt(5))/2

Find the zeros of x^2+x-31=0

The zeros of x^2+x-31=0 are x=(-1+5sqrt(5))/2 ,x=(-1-5sqrt(5))/2

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x^{2} + x - 31 = 0

x = \frac{- 1 + 5 5}{2}, x = \frac{- 1 - 5 5}{2}

Decimal Notation

x = 5.09016 \dots, x = - 6.09016 \dots

Solution steps

x^{2} + x - 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 31 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 31) = 55

x_{1, 2} = \frac{- 1 \pm 5 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 5 5}{2 \cdot 1}, x_{2} = \frac{- 1 - 5 5}{2 \cdot 1}

x = \frac{- 1 + 5 5}{2 \cdot 1} : \frac{- 1 + 5 5}{2}

x = \frac{- 1 - 5 5}{2 \cdot 1} : \frac{- 1 - 5 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 5 5}{2}, x = \frac{- 1 - 5 5}{2}

- 3 + 2 x > 9

\frac{98}{2 ^{\frac{1}{2}}}

y^{2} z - yz

(x - 1)^{2} < x (x - 4) + 8

5 x^{2} - 39 x - 8

What are the solutions to the equation x^2+x-31=0 ?
The solutions to the equation x^2+x-31=0 are x=(-1+5sqrt(5))/2 ,x=(-1-5sqrt(5))/2
Find the zeros of x^2+x-31=0
The zeros of x^2+x-31=0 are x=(-1+5sqrt(5))/2 ,x=(-1-5sqrt(5))/2