What are the solutions to the equation (z+8)^2=-15 ?

The solutions to the equation (z+8)^2=-15 are z=sqrt(15)i-8,z=-sqrt(15)i-8

Find the zeros of (z+8)^2=-15

The zeros of (z+8)^2=-15 are z=sqrt(15)i-8,z=-sqrt(15)i-8

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(z + 8)^{2} = - 15

z = 15 i - 8, z = - 15 i - 8

Solution steps

(z + 8)^{2} = - 15

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 8 = - 15 : z = 15 i - 8

Solve

z + 8 = - - 15 : z = - 15 i - 8

The solutions to the quadratic equation are:

z = 15 i - 8, z = - 15 i - 8

22 > 4 m - 2

(\frac{2 + i}{3 + 4 i} - \frac{2 i}{3 - 4 i})^{2}

\frac{1}{3} (x + 3) + \frac{1}{2} \geq - \frac{9}{2}

2 (1 - x) \geq 5 x

a^{2} - 4 a - 21

What are the solutions to the equation (z+8)^2=-15 ?
The solutions to the equation (z+8)^2=-15 are z=sqrt(15)i-8,z=-sqrt(15)i-8
Find the zeros of (z+8)^2=-15
The zeros of (z+8)^2=-15 are z=sqrt(15)i-8,z=-sqrt(15)i-8