What are the solutions to the equation 4x^2=-20 ?

The solutions to the equation 4x^2=-20 are x=sqrt(5)i,x=-sqrt(5)i

Find the zeros of 4x^2=-20

The zeros of 4x^2=-20 are x=sqrt(5)i,x=-sqrt(5)i

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4 x^{2} = - 20

x = 5 i, x = - 5 i

Solution steps

4 x^{2} = - 20

Divide both sides by

4

x^{2} = - 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 5, x = - - 5

- 5 = 5 i

- - 5 = - 5 i

x = 5 i, x = - 5 i

π - π

\frac{x}{4} + 1 = \frac{x}{4}

∣ - 11 ∣

4 z (2 z + 1) = - 6 z - 3

x (6 x - 1) - 3 (6 x - 1)

What are the solutions to the equation 4x^2=-20 ?
The solutions to the equation 4x^2=-20 are x=sqrt(5)i,x=-sqrt(5)i
Find the zeros of 4x^2=-20
The zeros of 4x^2=-20 are x=sqrt(5)i,x=-sqrt(5)i