What are the solutions to the equation -3x^2-15+5x=4 ?

The solutions to the equation -3x^2-15+5x=4 are x= 5/6-i(sqrt(203))/6 ,x= 5/6+i(sqrt(203))/6

Find the zeros of -3x^2-15+5x=4

The zeros of -3x^2-15+5x=4 are x= 5/6-i(sqrt(203))/6 ,x= 5/6+i(sqrt(203))/6

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- 3 x^{2} - 15 + 5 x = 4

x = \frac{5}{6} - i \frac{203}{6}, x = \frac{5}{6} + i \frac{203}{6}

Solution steps

- 3 x^{2} - 15 + 5 x = 4

Move

4

to the left side

- 3 x^{2} + 5 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 3 ) ( - 19 )}{2 ( - 3 )}

Simplify

5^{2} - 4 (- 3) (- 19) : 203 i

x_{1, 2} = \frac{- 5 \pm 203 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 5 + 203 i}{2 ( - 3 )}, x_{2} = \frac{- 5 - 203 i}{2 ( - 3 )}

x = \frac{- 5 + 203 i}{2 ( - 3 )} : \frac{5}{6} - i \frac{203}{6}

x = \frac{- 5 - 203 i}{2 ( - 3 )} : \frac{5}{6} + i \frac{203}{6}

The solutions to the quadratic equation are:

x = \frac{5}{6} - i \frac{203}{6}, x = \frac{5}{6} + i \frac{203}{6}

2 x < 10

- \frac{22}{2}

\frac{2}{2 ^{- 4}}

- \frac{4}{5} y \leq 12

2 x^{2} + 11 x + 9

What are the solutions to the equation -3x^2-15+5x=4 ?
The solutions to the equation -3x^2-15+5x=4 are x= 5/6-i(sqrt(203))/6 ,x= 5/6+i(sqrt(203))/6
Find the zeros of -3x^2-15+5x=4
The zeros of -3x^2-15+5x=4 are x= 5/6-i(sqrt(203))/6 ,x= 5/6+i(sqrt(203))/6