What are the solutions to the equation -4x^2+1040x-65100=0 ?

The solutions to the equation -4x^2+1040x-65100=0 are x=105,x=155

Find the zeros of -4x^2+1040x-65100=0

The zeros of -4x^2+1040x-65100=0 are x=105,x=155

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- 4 x^{2} + 1040 x - 65100 = 0

x = 105, x = 155

Solution steps

- 4 x^{2} + 1040 x - 65100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1040 \pm 104 0 ^{2} - 4 ( - 4 ) ( - 65100 )}{2 ( - 4 )}

104 0^{2} - 4 (- 4) (- 65100) = 200

x_{1, 2} = \frac{- 1040 \pm 200}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 1040 + 200}{2 ( - 4 )}, x_{2} = \frac{- 1040 - 200}{2 ( - 4 )}

x = \frac{- 1040 + 200}{2 ( - 4 )} : 105

x = \frac{- 1040 - 200}{2 ( - 4 )} : 155

The solutions to the quadratic equation are:

x = 105, x = 155

5 y + 25

50 = 0.1 x + 45.5

lo g_{3} (729) = x

\frac{3}{2} (8)

1 - 9 a^{4}

What are the solutions to the equation -4x^2+1040x-65100=0 ?
The solutions to the equation -4x^2+1040x-65100=0 are x=105,x=155
Find the zeros of -4x^2+1040x-65100=0
The zeros of -4x^2+1040x-65100=0 are x=105,x=155