What are the solutions to the equation 20z^2+7z-6=0 ?

The solutions to the equation 20z^2+7z-6=0 are z= 2/5 ,z=-3/4

Find the zeros of 20z^2+7z-6=0

The zeros of 20z^2+7z-6=0 are z= 2/5 ,z=-3/4

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20 z^{2} + 7 z - 6 = 0

z = \frac{2}{5}, z = - \frac{3}{4}

Solution steps

20 z^{2} + 7 z - 6 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 20 ( - 6 )}{2 \cdot 20}

7^{2} - 4 \cdot 20 (- 6) = 23

z_{1, 2} = \frac{- 7 \pm 23}{2 \cdot 20}

Separate the solutions

z_{1} = \frac{- 7 + 23}{2 \cdot 20}, z_{2} = \frac{- 7 - 23}{2 \cdot 20}

z = \frac{- 7 + 23}{2 \cdot 20} : \frac{2}{5}

z = \frac{- 7 - 23}{2 \cdot 20} : - \frac{3}{4}

The solutions to the quadratic equation are:

z = \frac{2}{5}, z = - \frac{3}{4}

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What are the solutions to the equation 20z^2+7z-6=0 ?
The solutions to the equation 20z^2+7z-6=0 are z= 2/5 ,z=-3/4
Find the zeros of 20z^2+7z-6=0
The zeros of 20z^2+7z-6=0 are z= 2/5 ,z=-3/4