What are the solutions to the equation a^2=2a ?

The solutions to the equation a^2=2a are a=2,a=0

Find the zeros of a^2=2a

The zeros of a^2=2a are a=2,a=0

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a^{2} = 2 a

a = 2, a = 0

Solution steps

a^{2} = 2 a

Move

2 a

to the left side

a^{2} - 2 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0 = 2

a_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 1}, a_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 1}

a = \frac{- ( - 2 ) + 2}{2 \cdot 1} : 2

a = \frac{- ( - 2 ) - 2}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

a = 2, a = 0

- 4 lo g_{5} (x) - 5 \geq 3

- 3 (3)^{2} + 2 (3) + 1

4 x = \frac{5}{2} x - 4

∣ n ∣ + 4 < 12

x + x^{2} + 1 > 0

What are the solutions to the equation a^2=2a ?
The solutions to the equation a^2=2a are a=2,a=0
Find the zeros of a^2=2a
The zeros of a^2=2a are a=2,a=0